Standard smooth of free Kaehler differentials #
In this file we show a presentation independent characterization of being
standard smooth: An R-algebra S of finite presentation is standard smooth if and only if
H¹(S/R) = 0 and Ω[S⁄R] is free on {d sᵢ}ᵢ for some sᵢ : S.
From this we deduce relations of standard smooth with other local properties.
Main results #
IsStandardSmooth.iff_exists_basis_kaehlerDifferential: AnR-algebraSof finite presentation is standard smooth if and only ifH¹(S/R) = 0andΩ[S⁄R]is free on{d sᵢ}ᵢfor somesᵢ : S.Etale.iff_isStandardSmoothOfRelativeDimension_zero: AnR-algebraSis étale if and only if it is standard smooth of relative dimension zero.IsSmoothAt.exists_notMem_isStandardSmooth: IfSisR-smooth at a primep, it is standard smooth on a standard open containingp.
Notes #
For an example of an algebra with H¹(S/R) = 0 and Ω[S⁄R] finite and free, but
S not standard smooth over R, consider R = ℝ and S = R[x,y]/(x² + y² - 1) the
coordinate ring of the circle. One can show that then Ω[S⁄R] is S-free on ω = xdy - ydx,
but there are no f g : S such that ω = g df.
If H¹(S/R) = 0 and Ω[S⁄R] is free on {d sᵢ}ᵢ for some sᵢ : S, then S
is R-standard smooth.
An R-algebra S of finite presentation is standard smooth if and only if
H¹(S/R) = 0 and Ω[S⁄R] is free on {d sᵢ}ᵢ for some sᵢ : S.
If S is R-smooth at a prime p, then S is R-standard-smooth in a neighbourhood of p:
there exists a basic open p ∈ D(f) of Spec S such that S[1/f] is standard smooth.
If S is R-smooth, there exists a cover by basic opens D(sᵢ) such that
S[1/sᵢ] is R-standard-smooth.